pytimeparse2 1.7.1

This is a pytimeparse based project with the aim of optimizing functionality and providing stable support.

Copyright (c) 2021 Sergey Klyuykov <onegreyonewhite@mail.ru>

Licensed under the MIT License (see source file pytimeparse2.py for details).

A small Python library to parse various kinds of time expressions, inspired by this StackOverflow question.

The single function pytimeparse2.parse defined in the library parses time expressions like the following:

• 32m

• 2h32m

• 3d2h32m

• 1w3d2h32m

• 1w 3d 2h 32m

• 1 w 3 d 2 h 32 m

• 4:13

• 4:13:02

• 4:13:02.266

• 2:04:13:02.266

• 2 days, 4:13:02 (uptime format)

• 2 days, 4:13:02.266

• 5hr34m56s

• 5 hours, 34 minutes, 56 seconds

• 5 hrs, 34 mins, 56 secs

• 2 days, 5 hours, 34 minutes, 56 seconds

• 1.2 m

• 1.2 min

• 1.2 mins

• 1.2 minute

• 1.2 minutes

• 172 hours

• 172 hr

• 172 h

• 172 hrs

• 172 hour

• 1.24 days

• 5 d

• 5 day

• 5 days

• 5.6 wk

• 5.6 week

• 5.6 weeks

It returns the time as a number of seconds (an integer value if possible, otherwise a floating-point number):

>>> from pytimeparse import parse
>>> parse('1.2 minutes')
72

For months and years, the library does not consider complications such as leap- years and leap-seconds. Instead, it assumes “30 days for a month” and “365 days for a year” as the basis for calculations with those units.

• 2 mo

• 2 months

• 3y

• 3 years

• 1y2mo3w4d5h6m7s8ms

For better capability with dates, use keyword as_timedelta=True which mark for function returns value as datetime.timedelta or dateutil.relitivedelta.relativedelta (if installed):

>>> from pytimeparse import parse
>>> parse('24h', as_timedelta=True)
relativedelta(days=+1)

You can also forced disable dateutil support by calling disable_dateutil() before parse(...). For returning support call enable_dateutil().

>>> from pytimeparse import parse
>>> import datetime
>>> parse('1 day, 14:20:16')
138016
>>> str(datetime.timedelta(seconds=138016))
'1 day, 14:20:16'