SCOP (SOlver for Constraint Programming)

How to Install to Jupyter Notebook (Lab) and/or Google Colaboratory

pip install scop

How to use

See https://mikiokubo.github.io/scoptrial/ and https://www.logopt.com/scop2/

Here is an example.

"""
Example 1 (Assignment Problem):
Three jobs (0,1,2) must be assigned to three workers (A,B,C)
so that each job is assigned to exactly one worker.
The cost matrix is represented by the list of lists
Cost=[[15, 20, 30],
      [7, 15, 12],
      [25,10,13]],
where rows of the matrix are workers, and columns are jobs.
Find the minimum cost assignment of workers to jobs.
"""
from scop import Alldiff, Linear, Model

workers = ["A", "B", "C"]
Jobs = [0, 1, 2]
Cost = {
    ("A", 0): 15,
    ("A", 1): 20,
    ("A", 2): 30,
    ("B", 0): 7,
    ("B", 1): 15,
    ("B", 2): 12,
    ("C", 0): 25,
    ("C", 1): 10,
    ("C", 2): 13,
}

m = Model()
x = {}
for i in workers:
    x[i] = m.addVariable(name=i, domain=Jobs)

x_list = []
for i in x:
    x_list.append(x[i])

con1 = Alldiff("AD", x_list, weight="inf")

con2 = Linear("linear_constraint", weight=1, rhs=0, direction="<=")
for i in workers:
    for j in Jobs:
        con2.addTerms(Cost[i, j], x[i], j)

m.addConstraint(con1)
m.addConstraint(con2)

print(m)

m.Params.TimeLimit = 1
sol, violated = m.optimize()

if m.Status == 0:
    print("solution")
    for x in sol:
        print(x, sol[x])
    print("violated constraint(s)")
    for v in violated:
        print(v, violated[v])

Model: 
number of variables = 3  
number of constraints= 2  
variable A:['0', '1', '2'] = None 
variable B:['0', '1', '2'] = None 
variable C:['0', '1', '2'] = None 
AD: weight= inf type=alldiff  A B C ;  :LHS =0  
linear_constraint: weight= 1 type=linear 15(A,0) 20(A,1) 30(A,2) 7(B,0) 15(B,1) 12(B,2) 25(C,0) 10(C,1) 13(C,2) <=0 :LHS =0 

 ================ Now solving the problem ================ 

solution
A 0
B 2
C 1
violated constraint(s)
linear_constraint 37