Python function that generates a URL to a given S3 resource.
Project description
Python function that generates a URL to a given S3 resource.
Example
url_for_s3('static', bucket_name='my-cool-foobar-bucket',
scheme='https', filename='pics/logo.png')
Will return: https://my-cool-foobar-bucket.s3.amazonaws.com/static/pics/logo.png
Note: this function assumes that the given resource exists on S3 and is publicly accessible.
Based loosely on Flask-S3’s url_for().
For a complete, working Flask app that demonstrates url-for-s3 in action, have a look at flask-s3-save-example.
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- Tags: Python 2, Python 3
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