url-for-s3
Python function that generates a URL to a given S3 resource.
Example
url_for_s3('static', bucket_name='my-cool-foobar-bucket',
scheme='https', filename='pics/logo.png')Will return: https://my-cool-foobar-bucket.s3.amazonaws.com/static/pics/logo.png
Note: this function assumes that the given resource exists on S3 and is publicly accessible.
Based loosely on Flask-S3’s url_for().
For a complete, working Flask app that demonstrates url-for-s3 in action, have a look at flask-s3-save-example.
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Metadata
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Release files for url-for-s3 0.1.2
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Built distribution (wheel)
| File | Interpreter | ABI | Platform | Reset |
|---|---|---|---|---|
| url_for_s3-0.1.2-py2.py3-none-any.whl | Python 2, Python 3 | none | any | Details |
Release files / url_for_s3-0.1.2-py2.py3-none-any.whl
| Download URL | url_for_s3-0.1.2-py2.py3-none-any.whl |
|---|---|
| Size | 3.7 kB |
| Tags | Python 2 Python 3 |
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