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Label lines in matplotlib.

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Copyright (c) 2017 Corentin Cadiou

Permission is hereby granted, free of charge, to any person obtaining a copy
of this software and associated documentation files (the "Software"), to deal
in the Software without restriction, including without limitation the rights
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copies or substantial portions of the Software.

THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR
IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,
FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE
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SOFTWARE.

Description: # matplotlib-label-lines
[![Build Status](https://travis-ci.org/cphyc/matplotlib-label-lines.svg?branch=master)](https://travis-ci.org/cphyc/matplotlib-label-lines)
[![codecov](https://codecov.io/gh/cphyc/matplotlib-label-lines/branch/master/graph/badge.svg)](https://codecov.io/gh/cphyc/matplotlib-label-lines)
Label line using matplotlib.

From http://stackoverflow.com/questions/16992038/inline-labels-in-matplotlib (original code from NauticalMile).

## Install

Just do:
```bash
pip install matplotlib-label-lines
```
and then:
```python
import numpy as np
from matplotlib import pyplot as plt
from scipy.stats import loglaplace,chi2

from labellines import labelLine, labelLines

X = np.linspace(0,1,500)
A = [1,2,5,10,20]
funcs = [np.arctan,np.sin,loglaplace(4).pdf,chi2(5).pdf]

plt.subplot(221)
for a in A:
plt.plot(X,np.arctan(a*X),label=str(a))

labelLines(plt.gca().get_lines(),zorder=2.5)

plt.subplot(222)
for a in A:
plt.plot(X,np.sin(a*X),label=str(a))

labelLines(plt.gca().get_lines(),align=False,fontsize=14)

plt.subplot(223)
for a in A:
plt.plot(X,loglaplace(4).pdf(a*X),label=str(a))

xvals = [0.8,0.55,0.22,0.104,0.045]
labelLines(plt.gca().get_lines(),align=False,xvals=xvals,color='k')

plt.subplot(224)
for a in A:
plt.plot(X,chi2(5).pdf(a*X),label=str(a))

lines = plt.gca().get_lines()
l1=lines[-1]
labelLine(l1,0.6,label=r'$Re=${}'.format(l1.get_label()),ha='left',va='bottom',align = False)
labelLines(lines[:-1],align=False)

plt.show()
```

Platform: UNKNOWN

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